Two dice are thrown,
what is the probability of getting the sum being 8 or the sum being 10?
Solution:
Number of sample
points in throwing
two dice at a time is n(S)=36
Let A= {the sum being 8}
\ A= {(6,2), (5,3) , (4,4), (3,5) , (2,6)};
P(A) = 5/36
B = {the sum being 10}
\ B = {(6,4),
(5,5) (4,6)} ; P(B) = 3/36
A Ç B = { } ; n(A Ç B) = 0
\ The two events are mutually exclusive
\ P(A È B) = P(A) + P(B)
5 3
= --- + ---
36 36
8 2
= ----- = --
36 9
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